what would be the equation of a line that has a slope of -2 and passes through point (3,5)? Please help! Math test tomorrow:(
Try the form y = m x + b
where m is the slope and b is the y axis intercept.
We are given m. It is -2
so
y = -2 x + b
now we are give a point where x = 3 and y = 5
put those values in
5 = -2*3 + b
5 = -6 + b
b = 11
so in the end
y = -2x + 11
To find the equation of a line, we can use the slope-intercept form, which is given by y = mx + b, where m is the slope of the line, and b is the y-intercept.
Given that the slope (m) is -2 and the line passes through the point (3,5), we can use the point-slope form of the equation, which is given by:
(y - y1) = m(x - x1),
where (x1, y1) represents the coordinates of the given point.
Substituting the values we have:
(y - 5) = -2(x - 3).
Now, let's simplify this equation:
y - 5 = -2x + 6.
To get the equation in the slope-intercept form, we need to isolate y:
y = -2x + 6 + 5.
Simplifying further:
y = -2x + 11.
So, the equation of the line with a slope of -2 that passes through the point (3,5) is y = -2x + 11.