# CALCULUS

Find a formula for the inverse of the function.

y=x^2-x, x>=(greater than or equal to) 1/2

Please give me a step by step explanation. I think my algebra is wrong... Ty

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1. x = y^2 - y

y^2 - y + 1 = x + 1

(y-1)^2 = x + 1

y -1 = sqrt (x+1)

y = 1 + sqrt (x+1)

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2. noticed an error from line 2 to line 3

y^2 - y = x
y^2 - y + 1/4 = x + 1/4
(y - 1/2)^2 =(4x+1)/4

y - 1/2 = ±√(4x+1)/2

y = 1/2 ± √(4x+1)/2

= (1 ± √(4x+1) )/2 , x ≥ -1/4

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3. Whoops !

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4. I don't understand. Why are you adding 1/4? to both sides? I don't see how you are getting a quadratic formula from this. More importantly, thank you guys for the help!

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