How many ways can 3 students be chosen from a class of 16 to represent their class at a banquet?

a.3,360
b.1,680
c.1,120
d.560

its 560 ill come back with all the answers

To this day, a man once known as "Meeeeme" never returned with all the answers. Thank you. - Narrated by your Narrator: Narrator

english plz

Let's put an F in chat for this person known as Meeeeme.

To find the number of ways to choose 3 students from a class of 16, you can use the combination formula.

The formula for calculating combinations is given by C(n, r) = n! / (r!(n - r)!), where n is the total number of items and r is the number of items chosen.

In this case, n = 16 (total number of students in the class) and r = 3 (number of students to be chosen).

Plugging in these values, we can calculate C(16, 3) as:

C(16, 3) = 16! / (3!(16 - 3)!)
= 16! / (3! * 13!)
= (16 * 15 * 14 * 13!) / (3! * 13!)
= (16 * 15 * 14) / (3 * 2 * 1)
= 560

Hence, the number of ways to choose 3 students from a class of 16 is 560.

Therefore, the answer is option d. 560

C(3,16) = 16!/[13!(3!) ]

= 16*15*14/(3*2) = 16 *5*7 = 560