an object in completely submerged in a liquid of density .65 grams per cubic centimeter at a depth of 4 meters what is the total pressure on the object. State your answer in atmospheres.
I only get 3 tries and both my other attempts failed. Ill lose credit now please help!
4 meters is around 12 feet and 33 feet of water is about an atm but his is lighter than water, so total pressure will be about 1 1/4 atm including 1 atm at the surface
.65 grams/cc = 650 kg/m^3
pressure = 4 * 650 *9.81 Newtons /m^3 or Pascals
= 25,506 Pascals
but that is gage, not total pressure, add one atmosphere which is 101,325 Pascals
so
126831 Pascals
now convert to atm
126831 Pa/ 101325 Pa/atm = 1.25 atm
thanks so much!!!
You are welcome :)
To calculate the pressure on an object submerged in a liquid, you can use the formula:
Pressure = Density * gravitational acceleration * depth
In this case, the density of the liquid is given as 0.65 grams per cubic centimeter, and the depth is 4 meters. However, it is important to convert the density to the appropriate unit before using the formula.
1 gram per cubic centimeter is equal to 1000 kilograms per cubic meter (since there are 1000 grams in a kilogram and 1 cubic meter is equal to 1,000,000 cubic centimeters).
Therefore, the density of the liquid is 0.65 grams per cubic centimeter * (1000 kg/m^3 / 1 g/cm^3) = 650 kg/m^3.
Now, we can use the given values in the formula:
Pressure = 650 kg/m^3 * 9.8 m/s^2 * 4 m
Calculating this, we get:
Pressure = 25,840 Pascal
To convert Pascal to atmospheres, you can use the conversion factor:
1 atmosphere = 101,325 Pascal
Therefore, the pressure on the object is:
Pressure = 25,840 Pascal / 101,325 Pascal per atmosphere
Calculating this, we get:
Pressure = 0.255 atmospheres (rounded to the nearest thousandth)
So the total pressure on the object is approximately 0.255 atmospheres.