What volume of a solution that is 15.7 % (w/w) lolinic acid (density = 1.64 g/mL) contains 4.25 g of lolinic acid?
What is the molarity of a 20.2 % (w/w) solution of rossonic acid (423.6 g mol-1) that has a density of 1.78 g mL-1?
To find the volume of a solution that contains a certain mass of solute, we can use the equation:
Volume = Mass of solute / Concentration
For the first question, we are given the mass of lolinic acid (4.25 g) and the concentration (15.7% w/w). First, we need to convert the given concentration to a decimal value:
Concentration = 15.7 / 100 = 0.157
Next, we can calculate the volume of the solution using the equation:
Volume = Mass of solute / Concentration
Volume = 4.25 g / 0.157
To calculate the molarity of a solution, we need to use the equation:
Molarity = (Mass of solute / Molar mass) / Volume
For the second question, we are given the concentration (20.2% w/w), molar mass (423.6 g/mol), and density (1.78 g/mL). Again, we need to convert the given concentration to a decimal value:
Concentration = 20.2 / 100 = 0.202
Next, we can calculate the mass of the solute in the solution using the equation:
Mass of solute = Volume x Density
Mass of solute = 1 mL x 1.78 g/mL
Then we can calculate the molarity using the equation:
Molarity = (Mass of solute / Molar mass) / Volume
Molarity = (1.78 g / 423.6 g/mol) / 1 mL
Remember to match the units in the equation to ensure accurate calculations.