# physics

A man steps off a 100 m diving platform. How long will it take him to
drop the &#133;first 50 m? How long will it take him to drop the second 50 m?

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1. Vo*t + 0.5g*t^2 = 100-50 = 50
0 + 4.9t^2 = 50
t^2 = 10.20
t = 3.19 s.

V = Vo + g*t = 0 + 9.8*3.19 = 31.3 m/s =
The velocity after the 1st 50 m drop =
The initial velocity (Vo) for the 2nd 50 m drop.

31.3*t + 4.9t^2 = 50
4.9t^2 + 31.3t - 50 = 0
t = 1.32 s.(Use Quad. Formula).

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posted by Henry

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