physics

When a bullet leaves a barrel of a rifle, it is moving 640 m/s. If the barrel is 1.20 m long, and if the bullet undergoes constant acceleration while within the barrel, how long after the rifle is fired will the bullet emerge from the end of the barrel?

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asked by Chavez
  1. a=(V^2-Vo^2)/2d = (640^2-0)/2.4=170,667
    m/s^2.

    V = Vo + a*t
    t=(V-Vo)/a = (640-0)/170,667=0.00375 s.
    = 3.75 ms.

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    posted by Henry

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