math
If the rectangles width is trippled and its length is doubled the perimeter of the new rectangle is 92 centimeter greater than the original perimeter what is the area of the original rectangle?
asked by
annie

original perimeter = 2L + 2w
new length = 2L
new width = 3W
new perimeter = 4L + 6w
4L+6w  (2L+2w) = 92
2L + 4w = 92
L + 2w = 46
L = 462w
area of original = lw
= w(462w)
= 46w  2w^2posted by Reiny
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