A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of + 17.4 m/s, while the exiting water stream has a velocity of – 15.0 m/s. The mass of water per second that strikes the blade is 33.6 kg/s. Find the magnitude of the average force exerted on the water by the blade.

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  1. force = rate of change of momentum

    change of velocity = 15+17.4 = 32.4 m/s

    rate of change of momentum = mass per second * change of velocity

    = 33.6 kg/s * 32.4 m/s

    = 1089 kg m/s^2 or Newtons

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  2. 21

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