If 3 hexagons and 4 trapezoids cost 200 in total what of is the cost of each piece alone?
is that the whole question or are you missing somthing
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To find the cost of each piece alone, we can set up a system of equations based on the given information.
Let's represent the cost of one hexagon as "x" and the cost of one trapezoid as "y".
From the information given, we know that 3 hexagons and 4 trapezoids together cost a total of 200:
3x + 4y = 200
Now, we can solve this system of equations to find the values of x and y.
Since we have two equations and two variables, we can solve the system using substitution or elimination.
Let's solve it using the elimination method:
First, we'll multiply the first equation by 4 to eliminate the y term:
4(3x + 4y) = 4(200)
12x + 16y = 800
Now, we can subtract the second equation from this new equation:
(12x + 16y) - (6x + 8y) = 800 - 400
6x + 8y = 400
Now, we have a new equation:
6x + 8y = 400
We can multiply the first equation by 2 to simplify it:
2(3x + 4y) = 2(200)
6x + 8y = 400
As we can see, the new equation is identical to the second equation we obtained earlier. This means that the two equations are dependent, and they represent the same line.
In other words, the system of equations has infinitely many solutions, and we cannot determine the exact values of x and y. Therefore, we cannot determine the cost of each piece alone with the given information.