A glass window pane has an area of 3.00 m2 and a thickness of 0.600 cm. If the temperature difference

between its faces is 25.0°C, what is the rate of energy transfer by conduction through the window.

Well, it's not often that I get to talk about windows, but here we go! Let me calculate this for you.

First things first, I should mention that this might get a bit heavy on the technical side. So, let's not get too glass-eyed during the process. Get it? Glass-eyed? Because we're talking about a glass window pane? No? Alright, moving on.

To calculate the rate of energy transfer by conduction, we can use Fourier's law of heat conduction, which is Q = k × A × ΔT / d.

Where:
Q is the rate of energy transfer,
k is the thermal conductivity of the material (let's assume it's 1.0 W/(m·K) for glass),
A is the area of the window pane (which is 3.00 m² in this case),
ΔT is the temperature difference (25.0°C),
and d is the thickness of the glass (0.600 cm in this scenario).

Now, let's plug in the values and see what we get!

Q = (1.0 W/(m·K)) × (3.00 m²) × (25.0°C) / (0.00600 m)

Calculating this value, the rate of energy transfer by conduction through the window pane is approximately 1,250 W.

So, there you have it! The rate of energy transfer is 1,250 W. That's enough to make your window pane a pretty hot commodity! At least in terms of energy transfer.

To calculate the rate of energy transfer by conduction through the window, we can use the formula:

Q = (k * A * ΔT) / d

Where:
Q = rate of energy transfer (in watts)
k = thermal conductivity of the material (in watts per meter per kelvin)
A = area of the window (in square meters)
ΔT = temperature difference (in kelvin)
d = thickness of the window (in meters)

First, let's convert the thickness from centimeters to meters:

d = 0.600 cm = 0.600 / 100 m = 0.006 m

Now, we need to find the thermal conductivity of glass. The thermal conductivity of glass varies, but a typical value is around 1.0 W/mK.

Substituting the given values into the formula, we get:

Q = (1.0 * 3.00 * 25.0) / 0.006

Calculating this expression gives us the rate of energy transfer by conduction through the window.

To find the rate of energy transfer by conduction through the window, we need to use the formula for heat transfer by conduction:

Q = (k * A * ΔT) / d

Where:
Q is the rate of energy transfer by conduction,
k is the thermal conductivity of the material (glass in this case),
A is the area of the window pane,
ΔT is the temperature difference between the faces of the window, and
d is the thickness of the window pane.

First, we need to find the thermal conductivity of glass. The thermal conductivity of glass can vary depending on the type of glass, but for normal window glass, it is typically around 0.8 W/(m·K).

So, now we can plug in the given values into the formula and calculate the rate of energy transfer by conduction:

k = 0.8 W/(m·K) (thermal conductivity of glass)
A = 3.00 m^2 (area of the window pane)
ΔT = 25.0°C (temperature difference between the faces of the window)
d = 0.600 cm = 0.006 m (thickness of the window pane)

Q = (0.8 * 3.00 * 25.0) / 0.006
Q = 1000 W or 1 kW

Therefore, the rate of energy transfer by conduction through the window is 1 kilowatt (kW).