a train approaching a crossing changes speed from 25 m/s to 10 m/s in 240 s. How can the train's acceleration be described?
it is slowing down, the acceleratin is negative with respect to the forward direction.
To describe the train's acceleration, we can use the formula for acceleration:
Acceleration (a) = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 25 m/s
Final velocity (v) = 10 m/s
Time (t) = 240 s
Using the formula, we can calculate the acceleration:
Acceleration (a) = (10 m/s - 25 m/s) / 240 s
Simplifying the equation:
Acceleration (a) = (-15 m/s) / 240 s
Dividing the numerator by the denominator gives us:
Acceleration (a) = -0.0625 m/s²
Therefore, the train's acceleration can be described as -0.0625 m/s².
To describe the train's acceleration, we can use the formula for acceleration:
Acceleration (a) = (Final velocity - Initial velocity) / Time
Here, the initial velocity (v₀) is 25 m/s, the final velocity (v) is 10 m/s, and the time (t) is 240 s.
Plugging in these values into the formula, we get:
Acceleration (a) = (10 m/s - 25 m/s) / 240 s
Now we can subtract the velocities to find the change in velocity:
Acceleration (a) = (-15 m/s) / 240 s
Finally, we divide the change in velocity by the time to find the acceleration:
Acceleration (a) = -0.0625 m/s²
So, the train's acceleration can be described as -0.0625 m/s².