AP Chemistry

If 400 mL of 3.2 molar HCl solution is added to 300 mL of 2 molar NaOH solution, what will be the molarity of NaCl in the resulting solution? Answer in units of M

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  1. HCl + NaOH ==> NaCl + H2O
    mols HCl = M x L = 3.2 x 0.4 = 1.28
    mols NaOH = M x L = 2 x 0.3 = 0.6

    mols NaCl formed = 0.6
    M NaCl = mols/L = 0.6/(0.4+0.3) = ?

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  2. HCL + NAOH -> NaCL + H2)
    Mols HCL = M x L = 3.2 x 0.4 = 1.28
    Mols NaOH = M x L = 2 x 0.3 = 0.6

    mols NaCl formed = 1.28
    M NaCl = mols/L = 1.28/(.4 + .3) = 1.829

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