N2+3H2->2NH3
What volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia? (assume constant temp. and pressure.)
There is a long way and a short way. The long way uses conventional stoichiometry. The short way says that for an all gaseous reaction, we can omit changing everything to mols, making conversions, and changing back to liters. We can just operate in liters. Therefore, 1 liter of N2 will require 3 liters of H2 to produce 2 liters of NH3. So 5 liters of N2*(xx/yy) = zz liters H2.
To determine the volume of hydrogen required to react with five liters of nitrogen to produce ammonia, we need to use the balanced chemical equation and the concept of stoichiometry.
The balanced chemical equation given is:
N2 + 3H2 -> 2NH3
From the equation, we can see that 1 mole of nitrogen (N2) reacts with 3 moles of hydrogen (H2) to produce 2 moles of ammonia (NH3).
To calculate the volume of hydrogen, we need to follow these steps:
Step 1: Convert the given volume of nitrogen to moles.
Since we know the volume of nitrogen is 5 liters, we need to convert it to moles using the ideal gas law equation:
PV = nRT
Where:
P = Pressure (assuming constant)
V = Volume (given as 5 liters)
n = Number of moles (what we need to find)
R = Ideal gas constant
T = Temperature (assuming constant)
Step 2: Use the stoichiometry from the balanced equation to relate moles of nitrogen (N2) to moles of hydrogen (H2).
From the balanced equation, we know that 3 moles of hydrogen react with 1 mole of nitrogen. So, by using the ratios, we can determine the moles of hydrogen required.
Step 3: Convert the moles of hydrogen back to volume using the ideal gas law equation.
Let's go through the calculations:
Step 1: Convert the given volume of nitrogen to moles.
Since we don't have the value for pressure and temperature, we can assume them to be constant. Let's say the temperature is 273K.
Using the ideal gas law equation: PV = nRT
Assuming atmospheric pressure (1 atm), we have: (1 atm) * (5 liters) = n * (0.0821 L.atm/mol.K) * (273K)
Solving for n, we find:
n = (1 * 5) / (0.0821 * 273)
Step 2: Use the stoichiometry from the balanced equation to relate moles of nitrogen (N2) to moles of hydrogen (H2).
From the balanced equation: 1 mole of nitrogen (N2) reacts with 3 moles of hydrogen (H2).
So, the moles of hydrogen required will be 3 times the moles of nitrogen.
Step 3: Convert the moles of hydrogen back to volume using the ideal gas law equation.
Using the ideal gas law equation: PV = nRT
Assuming the same pressure (1 atm) and temperature (273K) as in Step 1, we have: V = (n * 0.0821 * 273) / 1
By following these steps and performing the calculations, you can determine the volume of hydrogen necessary to react with five liters of nitrogen to produce ammonia.
To determine the volume of hydrogen necessary to react with five liters of nitrogen to produce ammonia, we need to use the balanced chemical equation:
N2 + 3H2 → 2NH3
According to the equation, the stoichiometric ratio between nitrogen and hydrogen is 1:3. This means that for every 1 mole of nitrogen, we need 3 moles of hydrogen.
Let's convert the given volume of nitrogen into moles using the ideal gas law equation:
PV = nRT
Where:
P = pressure (assumed constant)
V = volume (given as 5 liters)
n = number of moles of nitrogen (to be determined)
R = gas constant
T = temperature (assumed constant)
Rearranging the equation to solve for moles of nitrogen (n):
n = PV / RT
Assuming constant temperature and pressure, we can ignore them. So the equation becomes:
n = V / R
Substituting the given values:
n = 5 L / R
Now, since we know that the stoichiometric ratio between nitrogen and hydrogen is 1:3, we can determine the moles of hydrogen required. For 1 mole of nitrogen, we need 3 moles of hydrogen.
Therefore, the moles of hydrogen required would be:
3 x n
Now, to convert the moles of hydrogen into volume, we again use the ideal gas law equation:
V = nRT / P
Assuming constant temperature and pressure, we can ignore them. So the equation becomes:
V = n / R
Substituting the values:
V = (3 x n) / R
Combining the formulas, we get:
V = 15 L / R
Therefore, the volume of hydrogen necessary to react with five liters of nitrogen to produce ammonia is 15 L divided by the gas constant (R).