# Physics

A ball player catches a ball 3.33s after throwing it vertically upward.

a) with what speed did he throw it?

b) what height did it reach?

1. 👍 0
2. 👎 0
3. 👁 3,708
1. time in air = 3.33
so
time ascending = 3.33/2 = 1.665

v = 0 at top = Vi - 9.81 (1.665)
so
Vi = 16.3 m/s

average speed up = 16.3/2
time up = 1.665
so distance up = 13.6 meters

1. 👍 2
2. 👎 1
posted by Damon

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