the perimeter of a rectangular garden is 40 meters. the length of the garden is 1 meter less than twice its with. what are the dimensions of the garden?
2(w + 2w-1) = 40
2(3w-1) = 40
3w-1 = 20
3w = 21
w = 7
so, the garden is 7 x 13 meters
To find the dimensions of the garden, we can set up an equation based on the given information.
Let's assume the width of the garden is "w" meters. According to the problem, the length of the garden is 1 meter less than twice its width. Therefore, the length can be represented as 2w - 1 meters.
The perimeter of a rectangle is the sum of all its sides. In this case, the perimeter is given as 40 meters. The formula for the perimeter of a rectangle is P = 2(l + w), where P denotes the perimeter, l denotes the length, and w denotes the width.
Substituting the given values into the formula, we have:
40 = 2((2w - 1) + w)
Simplifying the equation:
40 = 2(3w - 1)
40 = 6w - 2
42 = 6w
w = 7
So, the width of the garden is 7 meters.
To find the length, we can substitute the value of w into the expression for the length:
Length = 2w - 1
Length = 2(7) - 1
Length = 13
Thus, the dimensions of the garden are 7 meters (width) and 13 meters (length).
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