chemistry

I'm not sure how to solve this:

If 125 cal of heat is applied to a 60.0-g piece of copper at 20.0∘C , what will the final temperature be? The specific heat of copper is 0.0920 cal/(g⋅∘C). Express the final temperature numerically in degrees Celsius

Thanks

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asked by mysterychicken

  1. heatgained= mass*c*(Tf-Ti)

    Tf= 125/(60*.0920) + 20

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    posted by bobpursley

  2. Good to hear from you again, MC. How is sister doing?

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    posted by bobpursley

  3. I'm sorry, I haven't really understood what you've done. could you maybe break it down for me? I'm new at this whole chem thing. What is Tf and Ti?
    She's good, she's about to get her degree in education!

    Thanks
    -MC

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    posted by mysterychicken

  4. Tf is the final temperature, Ti is the initial temperature.

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    posted by bobpursley

  6. I started from heat=mc deltaTemp
    then solved for final temperature Tf

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    posted by bobpursley

  7. So what I'm getting as I set up the equation is 60g x 125 x 60
    and that doesn't seem right

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    posted by mysterychicken

  8. Hmmmm. that is far from right.

    Heatgained= mass*specificheat*change in temp

    change in temp= heatgaind/(specificheat*mass)

    change in temp= 125cal/(.0920cal/gC * 60g) = 33.6 check that

    chaknge in temp= finaltemp-initial temp

    so final temp= 33.6+20 C

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    posted by bobpursley

  9. 53.6 c

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    posted by James

  10. 47.6

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    posted by Einstein

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