# Science

A ball is thrown upward at 20 metres per second off the top of a building that is 12 m high.

What is the height of the ball above the ground at its highest poin?

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1. v = Vi - g t
0 = 20 - 9.81 t at top when v = 0
t = 2.04 seconds
h = 12 + Vi t -(1/2) g t^2
h = 12 + 20(2.04) -4.9(2.04)^2
h = 32.4 meters

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posted by Damon

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