calculus

i am on "rolles and the mean value theorem" and was just wondering, when i am doing rolles, do i really need to find the exact value of x where f'(c) = 0?

for example:

f(x) = (x+4)^2 (x-3) on [-4,3]
i get to:
3x^2+10x-8=7

then i don't know if i then need to find the exact value of x or can i say:
1.2<x<1.3

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asked by eric
  1. yes. the mean value theorem lets you pick any interval, but Rolle's theorem says f(a) = f(b). It's just a special case of the MVT where f'(c) = 0. Your interval here meets that condition.

    As for your exact value, forget about decimal approximations.

    (-5±√70)/3 is exact. f'(1.25) is not zero.

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    posted by Steve
  2. how did you get (-5 +/- sqrt(70))/3

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    posted by eric
  3. I assumed you wanted the roots of your equation

    3x^2+10x-8=7

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    posted by Steve

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