Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.0928 V. How much work is done by the electric force when a sodium ion (charge = +e) moves from the outside to the inside?
no idea how to do this can i just have the step by step instructions with the formulas?
work=charge*voltage
Sure! Here's a step-by-step guide on how to solve this problem:
Step 1: Understand the problem
The problem asks for the work done by the electric force when a sodium ion moves from the outside to the inside of a cell. We are given the potential difference between the outside and inside of the cell.
Step 2: Recall the formula for electric potential
The electric potential difference (V) is given by the equation:
V = ΔU/q
Where ΔU is the change in electric potential energy and q is the charge.
Step 3: Rearrange the formula to solve for ΔU
Rearrange the formula to solve for ΔU:
ΔU = V * q
Step 4: Plug in the given values
Substitute the values into the formula:
ΔU = (0.0928 V) * (+e)
Step 5: Calculate the work done
The work done (W) is equal to the change in potential energy:
W = ΔU
Step 6: Simplify the expression
Since the charge of a sodium ion is +e (unit charge), we can simplify the expression:
W = (0.0928 V) * (+e)
Step 7: Calculate the work done
The value of the elementary charge, e, is approximately 1.602 x 10^-19 coulombs. You can multiply the potential difference (V) by the elementary charge (+e) to find the work done:
W = (0.0928 V) * (1.602 x 10^-19 C)
Step 8: Evaluate the calculation
Multiply the given values to obtain the work done in Joules (J).
That's it! By following these steps and plugging in the values correctly, you can determine the work done by the electric force when a sodium ion moves from the outside to the inside of the cell.