Calculus

Find the critical numbers of the function.
h(t) = t3/4 − 5t1/4

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asked by Anna
  1. h = t^(3/4) - 5t^(1/4)
    h' = 3/4 t^(-1/4) - 5/4 t^(-3/4)
    = (3√t-5) / 4t^(3/4)

    h' is undefined at t=0
    h' = 0 at t = 25/9

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    posted by Steve

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