(a)What is the pH of a solution made by combining 200 mL of 0.1 M Lactic Acid with 300 mL of 0.075 M sodium lactate? (b) If 20 mL of 0.4 M HCl is added to the solution from (a) what is the resulting pH?

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  1. Use the Henderson-Hasselbalch equation for a.
    pH = pKa + log(base)/(acid)

    millimols acid = 200 x 0.1 = 20
    millimols base = 300 x 0.075 = 22.5
    millimols HCl added = 20 x 0.4 = 8

    Set up an ICE chart.
    .........lactate + H^+ ==> lactic acid

    Plug the E line into another HH equation and solve for pH. Adding acid should decrease the pH.

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