Math

2 Gears are in their starting position.
Gear 1 has 6 teeth.
Gear 2 has 8 teeth.
As gear 1 turns, it causes gear 2 to turn at a different rate.
Gear 1 is rotated until the two gears are back at starting position.
What is the minimum number of rotations Gear 1 requires to return to it's starting position?

I know the answer is 4 rotations but I don't understand the proper reason why?

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  1. least common multiple of 6 and 8 is 24 teeth clashing

    that is 4 turns of the 6 and 3 turns of the 8

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    posted by Damon
  2. oooohh ok that makes sense! thanks!!

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    posted by Bethany
  3. You are welcome :)

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    posted by Damon
  4. 4 because l.c.m. of 6 & 8

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    posted by jamie
  5. impossible boi

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    posted by swag

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