Hi so im reviewing or our long test tomorrow on combined gas law and lussac's
well here, combined gas law i find it (maybe ) confusing to do this one, because theres no right answers because it is a practice exercise..
what i know on combined gas law is that pressure is inversely proportional to the volume.pressure directly prporional to temperature. i got hooked up in these problem where all (P,V,T) are decreased ( the way i solved it )
here it is :
a gas measures 10 ml at 27 degrees celsius and 760 mm hg. what will be the volume of the gas at 15 degrees celsius and 750 mm hg ? help me please
combined gas law:
p1V1/T1=P2V2/T2
you are looking for V2
V2=P1/P2 * V1*T2/T1
= 760/750 * 10ml*(15+273)/(27+273)
760/750*10*285/300=9.595
To solve this problem using the combined gas law, you need to remember the relationship between pressure, volume, and temperature. The combined gas law equation is as follows:
(P1 * V1) / T1 = (P2 * V2) / T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.
In this case, we are given the initial conditions as:
P1 = 760 mm Hg (pressure at 27 degrees Celsius)
V1 = 10 mL (volume at 27 degrees Celsius)
T1 = 27 degrees Celsius (temperature at 27 degrees Celsius)
And we need to find the final volume, V2, at the given conditions:
P2 = 750 mm Hg (pressure at 15 degrees Celsius)
T2 = 15 degrees Celsius (temperature at 15 degrees Celsius)
To solve this problem, we can rearrange the combined gas law equation to solve for V2:
V2 = (P2 * V1 * T1) / (P1 * T2)
Substituting the given values:
V2 = (750 mm Hg * 10 mL * 27 degrees Celsius) / (760 mm Hg * 15 degrees Celsius)
Calculating the solution:
V2 = 6.56 mL
So, the volume of the gas at 15 degrees Celsius and 750 mm Hg would be approximately 6.56 mL.
Remember to double-check all calculations and units for accuracy before finalizing your answer.