Factor completely, the expression
2x^2+6x-20
I did 2(x^2+3x-10)
then it can go down to
2(x+5)(x-2)
Is this correct?
Thanks for checking my work
yes,
You can always check your factored answer by simply expanding it. You must get back the original.
Thank you
at first I stopped at the 2(x^2+3x-10) but I thought about it and realized it could be factored further.
To factor the given expression 2x^2 + 6x - 20 completely, you have made a good start by factoring out the common factor 2.
So your first step, factoring out 2, is correct: 2(x^2 + 3x - 10).
To factor the quadratic trinomial x^2 + 3x - 10 further, you need to find two numbers that multiply to give -10 and add up to 3.
The factors of -10 that add up to 3 are 5 and -2. Therefore, the trinomial can be factored as (x + 5)(x - 2).
Finally, you can combine your results to obtain the completely factored expression: 2(x + 5)(x - 2).
Therefore, your final answer, 2(x + 5)(x - 2), is correct. Well done!