physics

A jogger travels a route that has two parts. The first is a displacement of 2.15 km due south, and the second involves a displacement that points due east. The resultant displacement + has a magnitude of 3.95 km. (a) What is the magnitude of , and what is the direction of + as a positive angle relative to due south? (b) Suppose that - had a magnitude of 3.95 km. What then would be the magnitude of , and what is the direction of - relative to due south?

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  1. Y = -2.15 km.
    R = 3.95 km.

    a. sin A = Y/R = -2.15/3.95 = -0.54430
    A = -33o = 57o East of South.
    R = 3.95km[57o] East of South.

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    posted by Henry

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