In Cambridge, England, a seconds pendulum is 0.9942 m long. What is the free-fall acceleration in Cambridge? (Use 4 significant figures in your answer.)
T=2PIsqrt(l/g)
l/g= T^2/2PI
g= l*2PI/l use 3.14159 for pi or better.
0.1007
To find the free-fall acceleration in Cambridge, England, we can use the formula for the period of a pendulum:
T = 2π√(L / g)
Where:
T = period of pendulum (in seconds)
L = length of pendulum (in meters)
g = acceleration due to gravity (in m/s^2)
In this case, we are given the length of the seconds pendulum as 0.9942 m.
To find the acceleration due to gravity (g), we need to rearrange the formula as follows:
g = (4π^2L) / T^2
Now, we can substitute the given values into the formula:
g = (4π^2 * 0.9942) / T^2
However, we still need the period of the pendulum (T) in order to calculate the free-fall acceleration correctly. Unfortunately, the period is not provided in the question.
To obtain the period, we need to measure the time it takes for the pendulum to complete one full swing. This can be done using a stopwatch or any timing device.
Once we have the period, we can substitute its value back into the formula and calculate the free-fall acceleration in Cambridge, England.