One angle of a triangle measures 100. the other two angles are in a ratio of 3:5. What are the measures of those two angles?
3x+5x+100=180
-100 -100
3x+5x=80
8x=80
x=10
3(10)=30
5(10)=50
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let the ratio be 3x ,5x
the sum of all angles of triangle = 180
3x + 5x + 100 = 180
8x = 180 -100
x = 80/8
x = 10
now,
3x = 3 x 10
= 30
5x = 5 x 10
= 50
One angle of a triangle measures 100. the other two angles are in a ratio of 3:5. What are the measures of those two angles?
So 100 + 3x + 5x = 180
100 + 8x = 180
8x = 80
x = 10
Now plug it in to your ratio, which is 3:5 so 30 and 50,
30 + 50 + 100 = 180
let the two unknown angles be 3x and 5x
3x + 5x + 100 = 180
......
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i do not know the answer, i need help please
To find the measures of the two angles, we first need to determine the ratio between them. The ratio of 3:5 indicates that the smaller angle is three parts and the larger angle is five parts.
To find the total number of parts in the ratio, we add the two parts together: 3 + 5 = 8.
Next, we need to find the measures of the two angles using this ratio. We can do this by dividing the total angle (180 degrees in a triangle) by the total number of parts in the ratio:
180 degrees / 8 = 22.5 degrees per part.
Now, we can find the measures of the angles:
Smaller angle = 3 parts * 22.5 degrees per part = 67.5 degrees.
Larger angle = 5 parts * 22.5 degrees per part = 112.5 degrees.
Therefore, the measures of the two angles are 67.5 degrees and 112.5 degrees.