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One solution contains 20% acid and a second solution contains 50% acid. How many ounces of each solution should be mixed in order to have 60 ounces of a 30% acid solution?

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  1. amount of 20% solution to be used: x ounce
    amound of 50% solution to be used : 60-x

    .2x + .5(60-x) = .3(60)
    time 10
    2x + 5(60-x) = 3(60)
    2x + 300 - 5x = 180
    -3x = -120
    x = 40

    40 ounce of the 20% and 20 ounces of the 50% solution should be mixed.

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    posted by Reiny

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