Given the reactant side of the total ionic equation for the neutralization reaction of ammonium hydroxide (NH4OH) with hydrochloric acid (HCl), write the total ionic equation (also known as the complete ionic equation) by entering both the reactant and the product species, separated by the reaction arrow.

NH4+(aq)+OH−(aq)+H+(aq)+Cl−(aq)→ ?

Be sure to include the charges on the ionic species and the physical state of all the reactant and product species.

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==> NH4^+(aq) + Cl^-(aq) + H2O(l)

To write the total ionic equation, we need to separate all the ionic species that are dissociated in the reaction.

First, let's identify the ionic species in the reactant side and determine if they are soluble in water.

NH4+(aq) - Ammonium ion is soluble in water.
OH−(aq) - Hydroxide ion is soluble in water.
H+(aq) - Hydrogen ion is not a separate species in water since it exists as H3O+ (hydronium ion).
Cl−(aq) - Chloride ion is soluble in water.

Now, we can represent the dissociation of each soluble ionic species:

NH4+(aq) + OH−(aq) + H+(aq) + Cl−(aq) → NH4+(aq) + H2O(l) + H3O+(aq) + Cl−(aq)

Note that OH−(aq) reacts with H+(aq) to form water (H2O), and H+(aq) reacts with water to form H3O+(aq).

Therefore, the total ionic equation for the neutralization reaction of ammonium hydroxide with hydrochloric acid is:

NH4+(aq) + OH−(aq) + H+(aq) + Cl−(aq) → NH4+(aq) + H2O(l) + H3O+(aq) + Cl−(aq)