Calculus

the legs of a right triangle have lengths a and b satisfying a + b =10. which values of a and b maximize the area of the triangle?

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  1. area = (1/2) a b
    b = 10 - a

    area = (1/2) a (10 -a)

    = (1/2) 10 a - a^2

    If we were doing algebra we could find the vertex of this parabola but since you said calculus, we will use calculus
    dArea/da = 0 when max or min
    dArea/da = (1/2)(10 - 2 a)
    2 a = 10
    a = 5
    b = 5

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    posted by Damon
  2. Is not really okay.

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    posted by Alvin

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