the first aircraft has 47 more seats than the second aircraft. the third aircraft has 54 fewer seats than the second aircraft. if their total number of seats is 401, find the number of seats for each aircraft.

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  1. Let x = second, then x+47 = first and x-54 = third.

    x + (x+47) + (x-54) = 401

    Solve for x, then the others.

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    posted by PsyDAG

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