Mrs Lim is 41 years old and her daughter is 14 years old. How many years ago was Mrs Lim four times as old as her daughter?
41-x = 4(14-x)
To determine how many years ago Mrs. Lim was four times as old as her daughter, we can set up an equation. Let's assume the number of years ago is represented by "x".
We know that Mrs. Lim's age "x" years ago would be 41 - x, and her daughter's age "x" years ago would be 14 - x.
According to the problem, Mrs. Lim was four times as old as her daughter "x" years ago, so we can write the equation:
41 - x = 4(14 - x)
Now, we can solve this equation to find the value of "x" which represents the number of years ago.
Expanding the equation gives us: 41 - x = 56 - 4x
Combining like terms, we get: 3x = 56 - 41
Simplifying further, we have: 3x = 15
Finally, dividing both sides by 3 gives us: x = 5
Therefore, Mrs. Lim was four times as old as her daughter 5 years ago.