Question

suppose a ball is thrown upward from a height of 4.5 feet with an initial velocity of 21 feet per second. write an equation relating the time t and height h of the ball

Answer 1

h = 21t + 4.5

Answer 2

h(t) = 4.5 + 21t - 16t^2

Answer 3

Sorry, take Steve's answer.

Answer 4

thanks steve

Answer 5

[AI-generated answer — Explain Bot]

To write an equation relating the time (t) and the height (h) of the ball, we need to use the equations of motion for vertical motion under constant acceleration.

The equation that relates the height (h) of an object in vertical motion to time (t) is given by the formula:

h = h0 + v0t - 1/2gt^2

Where:
h = height of the ball at time t
h0 = initial height (4.5 feet)
v0 = initial velocity (21 feet per second)
g = acceleration due to gravity (approximately 32.2 feet per second squared)

Plugging the given values into the equation, we get:

h = 4.5 + 21t - 1/2(32.2)t^2

Therefore, the equation relating time (t) and height (h) of the ball is:

h = 4.5 + 21t - 16.1t^2