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Algebra
(x)/(x3)4(2x5)/(x+2) I posted something before this, so now this is how far I got. The answer I know is (5x^217x9)/(x3)(x+2) first I get (x)(x+2)/(x3)(x+2) (4)(x3)(x+2)/(x3)(x+2)(2x5)(x3)/(x3)(x+2) Then I get
asked by Sara on July 20, 2007 
Algebra
(x)/(x3)4(2x5)/(x+2) I posted something before this, so now this is how far I got. The answer I know is (5x^217x9)/(x3)(x+2) first I get (x)(x+2)/(x3)(x+2) (4)(x3)(x+2)/(x3)(x+2)(2x5)(x3)/(x3)(x+2) Then I get
asked by Sara on July 20, 2007 
Algebra
The answer in the book however says (5x^217x9)/(x3)(x+2) so I don't know what I am doing wrong, can you take me step by step through the problem. I have a lot of problems, but I think once I understand what I am doing wrong
asked by Sara on July 20, 2007 
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x/(x3)4(2x5)/(x+2) If the problem is this: x/(x  3)  4  (3x  5)/(x + 2) ...find a common denominator to start. The common denominator is (x  3)(x + 2), then convert each term using the common denominator. Here's a start:
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Solve: 5x3=11+12x; 17x3=11; 17x3+3=11+3= 17x=14; x= 14/17 is this right?
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(3+7x)(16x2+15x2) (3+1x)(12x+16+0+18x2) Q4: (15+13x2+14x2)+(13x+18x) Q5: (2x2+1+15x2+7+3)+(0x+17x) Q6: (18x+3)+(17x2+1x2+9+8+0x) Q7: (6x + 14)  (9x + 5) Q8: (14x2 + 13x + 12)  (7x2 + 20x + 4) Q9: Subtract 10x2 + 16x  15 from
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(3+7x)(16x2+15x2) (3+1x)(12x+16+0+18x2) Q4: (15+13x2+14x2)+(13x+18x) Q5: (2x2+1+15x2+7+3)+(0x+17x) Q6: (18x+3)+(17x2+1x2+9+8+0x) Q7: (6x + 14)  (9x + 5) Q8: (14x2 + 13x + 12)  (7x2 + 20x + 4) Q9: Subtract 10x2 + 16x  15 from
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What are the short term effects of Cocaine: When someone consumes this substance what effect will it have on their body, mind, and behavior? Please answer ASAP I really need the answer... and please don't give the website for me
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BobPursley..here it is:
Problem 1: (x2)/(3x+4)  6x/(x+1) What I did: Common denominator is: (3x+4)(x+1) (x2)(x+1)/(3x+4)(x+1)  6x(3x+4)/(x+1)(3x+4) [(x2)(x+1)  6x(3x+4)] / (x+1)(3x+4) (x^2  x  2  18x^2  24x) / (x+1)(3x+4) x^2  18x^2 = 17x^2
asked by Margie on March 4, 2007