Math

Ten years ago a man was three times as old as his son. In twelve more years, the son is three-fifths as old as his father. What were their ages 5 years ago?

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  1. if the man is now m and the son s,

    m-10 = 3(s-10)
    (3/5)(m+12) = s+12

    m-5 = 38
    s-5 = 16

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    posted by Steve

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