# AP Chemistry

Like all equilibrium constants, Kw varies somewhat with temperature. Given that Kw is 7.51×10−13 at some temperature, compute
the pH of a neutral aqueous solution at that temperature.

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1. ........H2O ==> H^+ + OH^-
I......liquid....0.....0
C......liquid....x......x
E.....liquid.....x......x

So Kw = (H^+)(OH^-)
Substitute and solve for H^+ and pH.

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