Use a graphical method to find a solution to the following system of equations in the interval –1 ≤ x ≤ 5:

y = x2 – 4x + 2
y = x + 2
The solution set to this system of equations in the interval –1 ≤ x ≤ 5 is

{}
{(2, 0)}
{(0, 2), (5, 7)}
{(2, 0), (7, 5)}

Why are you calling this trig ?

x^2 - 4x + 2 = x+2
x^2 - 5x = 0
x(x-5) = 0
x = 0 or x = 5

sub in those x's in either of the two equations to find the y, then choose your answer.

http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E2+–+4x+%2B+2%2C++y+%3D+x+%2B+2

I got choice 3 is that correct

of course

To find the solution to the system of equations using graphical method, we can plot the graphs of both equations on the same coordinate grid and find the points of intersection. The points of intersection represent the solutions to the system of equations.

First, let's plot the graph of the equation y = x^2 - 4x + 2. To do this, we can create a table of values by substituting different values of x into the equation and calculating the corresponding y-values.

For example, when x = -1:
y = (-1)^2 - 4(-1) + 2 = 7

When x = 0:
y = 0^2 - 4(0) + 2 = 2

When x = 1:
y = 1^2 - 4(1) + 2 = -1

When x = 2:
y = 2^2 - 4(2) + 2 = -2

When x = 3:
y = 3^2 - 4(3) + 2 = 1

When x = 4:
y = 4^2 - 4(4) + 2 = 2

When x = 5:
y = 5^2 - 4(5) + 2 = 2

Now, let's plot these points on the graph:

(-1, 7), (0, 2), (1, -1), (2, -2), (3, 1), (4, 2), (5, 2)

Next, let's plot the graph of the equation y = x + 2. This is a straight line with a slope of 1 and a y-intercept of 2. We can plot two points and draw a line connecting them.

When x = -1:
y = -1 + 2 = 1

When x = 5:
y = 5 + 2 = 7

Now, let's plot these points on the graph:

(-1, 1), (5, 7)

Finally, we can see that the graphs intersect at the point (2, 0). This means that the solution to the system of equations in the interval -1 ≤ x ≤ 5 is {(2, 0)}.