# AP Physics C

One dimension. In the figure, two point particles are fixed on an x axis separated by distance d. Particle A has mass mA and particle B has mass 5.00 mA. A third particle C, of mass 62.0 mA, is to be placed on the x axis and near particles A and B. In terms of distance d, at what x coordinate should C be placed so that the net gravitational force on particle A from particles B and C is zero

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1. well, B exerts a force G(mA)(5mA)/d^2 = 5GA^2/d^2

C exerts a force G(mA)(62mA)/x^2 = 62GA^2/x^2

we want the two forces to cancel (so C must be on the opposite side of A from B), so if A is at 0 and B is at d,

5/d^2 = 62/x^2
x^2 = 62d^2/5
x = -d√(62/5)

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2. OK. Your work got me pretty close, but the one thing you need to do to get the correct answer in the assignment is to take -√(particle c's mass/particle b's mass)

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