32. The area of a square postage stamp is 81/100 in. to the second power. What is the side length of the stamp?
33. The area of a square boxing ring is 484 ft. to the second power. What is the perimeter of the boxing ring?
1. area = s^2 = 81/100
s = 9/10
2. area = 484
so side + √484 = 22
so sum of 4 sides = 88
Two fishing boats depart a harbor at the same time, one traveling east, the other south. The eastbound boat travels at a speed 7 mi/h faster than the southbound boat. After seven hours the boats are 91 mi apart. Find the speed of the southbound boat.
9/10 in 2
484 to the second power is 234256 so the perimeter of that is 58564. your velcome!!
To find the side length of the square postage stamp, we can take the square root of its area.
32. The area of the square postage stamp is given as 81/100 in^2. To find the side length, we take the square root of the area:
Side length = √(Area)
Side length = √(81/100 in^2)
To simplify the square root, we can express the area as a fraction in simplified form:
Side length = √(81/100 in^2)
Side length = (√81)/ (√100) in
Side length = 9/10 in
Therefore, the side length of the postage stamp is 9/10 inch.
33. To find the perimeter of the square boxing ring, we need to know the length of one side. Since the area is given, we can find the side length by taking the square root of the area.
The area of the square boxing ring is given as 484 ft^2. To find the side length, we take the square root of the area:
Side length = √(Area)
Side length = √(484 ft^2)
Side length = 22 ft
Since a square has all equal sides, the side length is 22 ft, and the perimeter of the square boxing ring is given by:
Perimeter = 4 * Side length
Perimeter = 4 * 22 ft
Perimeter = 88 ft
Therefore, the perimeter of the boxing ring is 88 feet.