write each equation in slope-intercept form. then graph the line described by the equation.

3y+2x=12

now, I just did one like that. You do this one

m=-2/3

y-intercept= (0,4)

check please

To write the equation in slope-intercept form (y = mx + b), we need to isolate the y-term on one side of the equation.

Given equation: 3y + 2x = 12

Subtracting 2x from both sides, we have:
3y = -2x + 12

Dividing every term by 3, we get:
y = (-2/3)x + 4

Now that we have the equation in slope-intercept form, we can identify the slope and y-intercept.

The slope (m) of the line is -2/3, which means the line has a rise of -2 units and a run of 3 units. This implies that for every increase of 3 units in the x-coordinate, the y-coordinate decreases by 2 units.

The y-intercept (b) is 4, which means the line intersects the y-axis at the point (0, 4).

To graph the line represented by this equation, plot the y-intercept at (0, 4), and then use the slope to determine additional points. From the y-intercept, move 3 units to the right and 2 units down, and plot another point. Connect the two points with a straight line, and extend it in both directions.

The graph of the line described by the equation y = (-2/3)x + 4 would look like this:
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4 |
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x