Laura rented a car that costs $20 for the day plus $.12 for each mile driven. She returned the car later that day. Laura gave the sales person $50 and received change. Which inequality represents the possible number of miles m that she could have driven?
A. 50>0.12m+20
B. 50<0.12m+20
C. 50>0.12m-20
D.50<0.12m-20
I think it is D.
Thank You.
The answer is not D. $50 must be greater than the total cost.
If the answer were D, then this would imply that $50 is less than the total cost.
So is it A?
Yes, you are correct. $50 must be greater than the total cost of 0.12m + $20
Good job.
To solve this problem, we need to set up the equation that represents the total cost of renting the car. We know that Laura paid $20 for the day and an additional $0.12 for each mile driven. Let's denote the number of miles driven as "m".
The total cost of renting the car, C, can be expressed as:
C = $20 + $0.12m
We also know that Laura gave the salesperson $50 and received change after returning the car. This means that the total cost of renting the car must be less than $50. So the inequality representing the possible number of miles driven can be obtained as follows:
C < $50
$20 + $0.12m < $50
Now we can simplify the inequality:
0.12m < $30
To isolate the variable m, we divide both sides of the inequality by 0.12:
m < $30 / 0.12
Simplifying further:
m < 250
Therefore, the correct inequality representing the possible number of miles m that Laura could have driven is:
50 < 0.12m + 20
So, the correct answer is A, not D.
I hope this helps!