I have two questions for the same problem I need help with. The sum of 2 numbers is 56. The smaller number is 1/3 the bigger one. If x is the smaller one an equation for the numbers is:

a)x-y=56
b)xy=56
c)x/y=56
d)x+y=56
I want to say the answer's c but I'm not sure.

Another equation is:
a)x=y+3
b)x=y-3
c)x=1/3y
d)x=3y
I'm pretty sure d is the correct answer for this one, but I'm just checking.

If the sum of x and y is 56, then
x+y=56 must be one of the equations.

If 1/3 of the larger one is the smaller one, then 1/3(y) = x.

x + y = 56 ----- equation 1

x = 3y ----- equation 2

substitute, x in equation 2 to equation 1

3y + y = 56
y = 56/4
y = 14
then,x = 42

For the first problem, you correctly identified that the equation x/y = 56 doesn't satisfy the given conditions.

To find the correct equation, you need to analyze the information given. Suppose the smaller number is x and the larger number is y. It is given that the sum of the two numbers is 56, so the equation x + y = 56 represents this condition.

Additionally, it is stated that the smaller number x is 1/3 of the larger number y. This information can be written as x = (1/3)y.

Therefore, the correct equation for the numbers is x = (1/3)y and the answer is d) x + y = 56.

For the second problem, you correctly identified that the equation d) x = 3y satisfies the given condition.

Since it is given that x equals y plus 3, it can be written as x = y + 3. This equation describes the relationship between the two numbers.

Therefore, the correct equation for the numbers is x = y + 3 and the answer is b) x = y - 3.

Make sure to carefully read the problem and analyze the information given to find the correct equations.