# math

John has 8 quarters, 3 dimes,and 7 nickels in the change holder in his car. He uses 16 of those coins, totaling \$2.50, to buy some tacos. Which coins remain in the change holder?

a. 1 dime, 1 nickel
b. 1 dime, 1 quarter
c. 1 nickel, 1 quarter
d. 2 quarters
e. 2 nickels

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2. 👎 0
3. 👁 160
1. 8 Quarters + 3 Dimes + 7 Nickels = 21 coins

he uses 16 coins

21 - 16 = 5

he used 8 Quarters, 3 Dimes and 5 Nickels

therefore he has 2 Nickels left

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2. 👎 0
posted by Anon
2. but 8 Quarters, 3 Dimes and 5 Nickels = \$2.55

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2. 👎 0
posted by Thomas

18 coins to start and uses 16, 18-16=2

So 2 coins left over

8 quartes = 2.00

2 dimes = 0.20

6 nickels = 0.30

8+6+2=16 2.00+0.30+0.20 = 2.50

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2. 👎 0

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