Calculate the heat given off when 177 g of copper cools from 155.0 c to 22.0 c. The specific heat capacity of copper is 0.385 j/g c
-8995.14 J I believe.
q= 177g (.385 J/g C) (-132 C)
6.27x10^3
Well, that's one cool copper! Let's calculate the amount of heat given off using the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Given:
Mass (m) = 177 g
Specific heat capacity (c) = 0.385 J/g°C
Change in temperature (ΔT) = 155.0°C - 22.0°C = 133.0°C
Now let's plug in the values into the formula:
Q = (177 g) * (0.385 J/g°C) * (133.0°C)
Calculating that gives us:
Q ≈ 8728.485 J
So, approximately 8728.485 Joules of heat are given off when 177 g of copper cools from 155.0°C to 22.0°C. Don't worry, the copper knows how to chill!
To calculate the heat given off when the copper cools, we can use the equation:
Q = m * c * ΔT
where:
Q = heat energy (in joules)
m = mass of the copper (in grams)
c = specific heat capacity of copper (in joules/gram °C)
ΔT = change in temperature (in °C)
Given:
m = 177 g
c = 0.385 J/g °C
ΔT = (final temperature - initial temperature)
ΔT = (22.0 °C - 155.0 °C)
ΔT = -133.0 °C
Now we can substitute the given values into the equation:
Q = (177 g) * (0.385 J/g °C) * (-133.0 °C)
Q = - 8279.13 J
The negative sign indicates that heat is being given off. Therefore, when 177 g of copper cools from 155.0 °C to 22.0 °C, the heat given off is approximately -8279.13 J.