The Tigers won twice as many football games as they lost.They played 96 games. How many games did they win?
x = games won
y = games lost
Write two equations:
x + y = 96
x = 2y
Substitute the second equation into the first equation:
2y + y = 96
3y = 96
3y/3 = 96/3
y = 32
Solve for x. Put y value in either equation:
x = 2(32)
x = 64
x 2x = 96
x = 32
They lost 32 games.
Ratio of win : lost = 2 : 1 = 2x : x
2x+x = 96
3x = 96
x = 32
won = 2x = 64
lost = x = 32
To find out how many games the Tigers won, we need to use the information that they won twice as many games as they lost, and the total number of games they played, which is 96.
Let's represent the number of games they lost as 'L'. Since they won twice as many games as they lost, the number of games they won can be represented as '2L'.
We know that the total number of games they played is 96. So, we can write an equation:
L + 2L = 96
Simplifying the equation, we have:
3L = 96
To find the value of L, we divide both sides of the equation by 3:
L = 96 / 3
L = 32
Now that we know the number of games they lost, we can determine the number of games they won. Since they won twice as many games as they lost:
2L = 2 * 32
2L = 64
Therefore, the Tigers won 64 games.