The rate constant,K, for a given was determined at a number of temperatures. A graph of log K versus the reciprocal of the kelvin temperature yielded a straight line with a slope of -250 K. What is the activation energy of this reaction in Kj/mol?
For this question I got 2.08kj/mol

  1. 👍 0
  2. 👎 0
  3. 👁 95
  1. I don't have my calculator handy but that looks right to me.
    250 * about 8 = about 2000 J/mol

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chemistry

    A student tested the effect of temperature on the decomposition of N2O5. He found that the rate of the reaction at a lower temperature was 4.2 x 10–3 s–1 and the rate at a higher temperature was 1.6 x 101 s–1. What is wrong

    asked by Cortney on March 25, 2015
  2. chemistry

    The activation energy of a reaction is typically determined by calculating the rate constant for the reaction at two temperatures and then manipulating the Arrhenius equation. If you determine the reaction rate constants for a

    asked by danny on February 14, 2015
  3. chemistry

    Values of the rate constant for the decomposition of N2O5 at four different temperatures are as follows: T(K) k(s^-1) 658....2.14*10^5 673....3.23*10^5 688....4.81*10^5 703....7.03*10^5 The activation energy is 1.02*10^2 kJ/mol.

    asked by Brunette on October 14, 2012
  4. Math

    Someone verify if this is correct, please! 1. Draw a distance versus time graph that corresponds to the walk described below. Adam starts 8 m away from the motion sensor and walks in a straight line toward the sensor at a constant

    asked by Melinda on December 4, 2011
  5. Chemistry

    How do you do the inverse of absolute temperature? My kelvin temperatures are: 298 308 318 328 338 348 358 368 378 Taking the natural log of both sides of both sides of the equation gives ln(k) = ln(A) – E/RT. Thus, a graph of

    asked by Angie on September 25, 2012
  6. Thermodynamic

    The equilibrium constant of a reaction is determined at 2 different temperatures: at -181°C, Keq = 2770 at -11°C, Keq = 640

    asked by Sophie on November 1, 2014
  7. Chemistry

    What is the activation energy for a simple A->B fist order type of reaction with the following rate constants at different temperatures? Temp rate constant (k) 310K 1.77 x 10-1s-1 480K 3.22 x 10^2s-1

    asked by Kristi on December 7, 2011
  8. math

    The park currently contains 20 wolves and the park rangers are introducing additional wolves at the rate mt(12−t) wolves per month, 0≤t≤12 for some constant m>0 to be determined. However, the park rangers are concerned about

    asked by anne on February 21, 2016
  9. Calculus

    I also have these other four question I need help on please!! 1. The graph of y = f ′(x), the derivative of f(x), is shown below. Given f(4) = 6, evaluate f(0). A. -2 B. 2 C. 4

    asked by Justin on July 29, 2019
  10. chemistry

    A certain first order reaction has a rate constant of 3.75x10^-2 s^-1 at 25.0C. What is the value of k at 70.0C when the activation energy is 135 kj/mol? Would I use the formula K=Ae ^-Ea/RT even though I have two temperatures?

    asked by student on March 14, 2012

More Similar Questions