Balance KCLO3 ---> KCl + O2
2KClO3 ---> 2KCl + 3O2
To balance O, multiply left side by 3 and the right side by 2:
2 KClO3 ---> KCl + 3 O2
Now to balance the KCl, you multiply the right side by 2:
2 KClO3 ---> 2 KCl + 3 O2
That should be it!
Correction:
First sentence should read "multiply left side by 2 and right side by 3."
Sorry for any confusion.
To balance the equation:
Step 1: Start by counting the number of each type of atom on both sides of the equation.
On the left side:
1 K, 1 Cl, and 3 O
On the right side:
1 K, 1 Cl, and 2 O
Step 2: Begin by balancing the atoms that appear in the fewest number on each side of the equation. In this case, the Cl atoms are already balanced.
Next, balance the K atoms by adding a coefficient of 2 in front of KCl on the right side of the equation:
KCLO3 ---> 2 KCl + O2
Now we have:
2 K, 2 Cl, and 2 O on the right side.
Step 3: Balance the O atoms by adding a coefficient of 3/2 in front of O2 on the right side of the equation:
KCLO3 ---> 2 KCl + 3/2 O2
Now we have:
2 K, 2 Cl, and 3 O on the right side.
Step 4: To eliminate the fractional coefficient, multiply all coefficients by 2:
2 KCLO3 ---> 4 KCl + 3 O2
Now the equation is balanced with equal numbers of each type of atom on both sides.