algebra 2

complete the square
2x^2-4x-1=0

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  1. solve by completing the square ??

    first divide by 2 and move the constant to the right ...

    x^2 - 2x = 1
    add 1 to both sides
    x^2 - 2x + 1 = 1 + 1
    (x-1)^2 = 2
    x-1 = ± √2

    x = 1 ± √2

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    posted by Reiny

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