Calculus

Water is leaking out of a pool at a rate of 4 cubic inches per second, what is the rate of change of the height of the water at the instant the volume equals 20ft cubic feet

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asked by Eric
  1. V= (l)(w)(h)
    since the length and width do not change, only V and h.

    dV/dt = (lw) dh/dt

    We must have the same units,
    20 cubic feet = 20(12^3) or 34560 cubic inches
    when V = 34560 and dV/dt = -4
    34560 = (lw) h
    lw = 34560/h

    -4 = 34560/h dh/dt
    dh/dt = -h/8640 inches/second

    Are you sure there were no other units given?

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    posted by Reiny

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